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a(n) = n^6 mod 23.
0

%I #15 Dec 26 2023 21:21:38

%S 0,1,18,16,2,8,12,4,13,3,6,9,9,6,3,13,4,12,8,2,16,18,1,0,1,18,16,2,8,

%T 12,4,13,3,6,9,9,6,3,13,4,12,8,2,16,18,1,0,1,18,16,2,8,12,4,13,3,6,9,

%U 9,6,3,13,4,12,8,2,16,18,1,0,1,18,16,2,8,12,4,13,3,6,9,9,6,3,13,4,12,8,2

%N a(n) = n^6 mod 23.

%H <a href="/index/Rec#order_23">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%F a(n) = a(n-23). - _Wesley Ivan Hurt_, Dec 26 2023

%t PowerMod[Range[0,90],6,23] (* or *) PadRight[{},90,{0,1,18,16,2,8,12,4,13,3,6,9,9,6,3,13,4,12,8,2,16,18,1}] (* _Harvey P. Dale_, Jul 18 2021 *)

%o (Sage) [power_mod(n,6,23)for n in range(0, 89)] # _Zerinvary Lajos_, Nov 06 2009

%o (PARI) a(n)=n^6%23 \\ _Charles R Greathouse IV_, Apr 06 2016

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, May 13 2002