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Let M_n be the n X n matrix with M_n(i,j)=i^3/(i+j); then a(n)=1/det(M_n).
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%I #5 Mar 30 2012 18:38:57

%S 2,9,200,30625,38896200,461231139600,55435389494284800,

%T 71735516141608609290000,1046764828663084040608098000000,

%U 178655433262265936739987483031412640000

%N Let M_n be the n X n matrix with M_n(i,j)=i^3/(i+j); then a(n)=1/det(M_n).

%o (PARI) for(n=1,15,print1(1/matdet(matrix(n,n,i,j,i^3/(j+i))),","))

%K easy,nonn

%O 1,1

%A _Benoit Cloitre_, Apr 21 2002