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a(n) = (n-1)!-n^tau(n)/n^2.
0

%I #7 Jan 20 2024 18:49:43

%S 0,1,2,23,84,719,4976,40311,362780,3628799,39896064,479001599,

%T 6227020604,87178290975,1307674363904,20922789887999,355687427991024,

%U 6402373705727999,121645100408672000,2432902008176639559

%N a(n) = (n-1)!-n^tau(n)/n^2.

%C n and a(n) have the same parity.

%t Table[(n - 1)! - n^DivisorSigma[0, n]/n^2, {n, 2, 25}] (* _Wesley Ivan Hurt_, Jan 20 2024 *)

%Y Cf. A062758.

%K easy,nonn

%O 2,3

%A _Benoit Cloitre_, Apr 08 2002