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%I #10 Feb 14 2021 12:47:23
%S 1,2,3,4,5,9,10,11,12,13,14,15,16,17,27,28,29,30,31,32,88,89,90,91,92,
%T 93,94,95,96,97,98,99,136,137,138,139,140,141,142,143,144,145,146,147,
%U 289,290,291,292,293,1004,1005,1006,1007,1008,1009,1010,1011,1012,1013
%N Numbers k such that the denominator of (Sum_{j=1..k} 1/j)^3 equals the denominator of Sum_{j=1..k} 1/j^3.
%F Numbers k such that A002805(k)^3 = A007409(k).
%K easy,nonn
%O 1,2
%A _Benoit Cloitre_, Mar 27 2002
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