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Numbers k such that prime(k)^3 == prime(k+1)^3 (mod k).
1

%I #14 Apr 06 2020 08:06:21

%S 1,2,4,7,9,18,26,79,139,219,248,657,1505,11246,19999,62608,368172,

%T 553598,646926,1241426,1562457,1568558,5098990,7889727,12866334,

%U 18941415,24647857,25355582,25869571,26114278,40784906,46699276,53532458,113309714,230702738,290702470

%N Numbers k such that prime(k)^3 == prime(k+1)^3 (mod k).

%C a(17) > 10^5. - _Michel Marcus_, Nov 22 2013

%o (PARI) isok(n) = Mod(prime(n+1), n)^3 == Mod(prime(n), n)^3; \\ _Michel Marcus_, Nov 22 2013

%Y Cf. A030078.

%K nonn

%O 1,2

%A _Benoit Cloitre_, Feb 06 2002

%E a(16) from _Michel Marcus_, Nov 22 2013

%E More terms from _Jinyuan Wang_, Apr 06 2020