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A067113 Let N = 0.149162536496481100121... = A001191, the concatenation of the squares. Then a(n) = sum of first n digits of N. 2

%I #7 Mar 16 2020 18:59:09

%S 1,5,14,15,21,23,28,31,37,41,50,56,60,68,69,70,70,70,71,73,74,75,79,

%T 83,84,90,99,100,109,115,117,119,124,126,131,137,139,147,156,159,161,

%U 165,168,174,175,179,179,179,183,187,188,192,200,204,209,211,220,225,232

%N Let N = 0.149162536496481100121... = A001191, the concatenation of the squares. Then a(n) = sum of first n digits of N.

%F a(n) ~ 4.5n (since 0.149162536... = A001191 is 10-normal).

%e a(5) = 1+4+9+1+6 = 21.

%K base,easy,nonn

%O 1,2

%A _Amarnath Murthy_, Jan 08 2002

%E Corrected and extended by Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003

%E Asymptotic formula from _Charles R Greathouse IV_, Oct 04 2008

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Last modified July 22 14:35 EDT 2024. Contains 374501 sequences. (Running on oeis4.)