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a(n) = n^(sum of digits of n).
2

%I #24 Dec 05 2024 18:04:19

%S 1,1,4,27,256,3125,46656,823543,16777216,387420489,10,121,1728,28561,

%T 537824,11390625,268435456,6975757441,198359290368,6131066257801,400,

%U 9261,234256,6436343,191102976,6103515625,208827064576,7625597484987

%N a(n) = n^(sum of digits of n).

%C Here 0^0 is taken to be 1. - _Alonso del Arte_, Sep 21 2019

%H Harry J. Smith, <a href="/A067040/b067040.txt">Table of n, a(n) for n = 0..400</a>

%F a(n) = n^A007953(n).

%F a(n) = n only when n is a power of 10. - _Alonso del Arte_, Sep 21 2019

%e a(12) = 12^(1 + 2) = 12^3 = 1728.

%e a(13) = 13^(1 + 3) = 13^4 = 28561.

%p a:= n-> n^add(i,i=convert(n, base, 10)):

%p seq(a(n), n=0..30); # _Alois P. Heinz_, Sep 21 2019

%t Table[n^(Plus@@IntegerDigits[n]), {n, 0, 99}] (* _Alonso del Arte_, Sep 14 2019 *)

%o (PARI) a(n) = {n^sumdigits(n)} \\ _Harry J. Smith_, Apr 29 2010

%Y Cf. A007953.

%K nonn,base,easy,changed

%O 0,3

%A _Amarnath Murthy_, Dec 29 2001

%E More terms from _Jason Earls_, Jan 18 2002