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Numbers k such that the digits of k (counted with multiplicity) are also digits of binomial(2k,k).
0

%I #9 Oct 07 2023 21:37:55

%S 5,8,12,14,15,16,20,22,23,24,25,29,31,32,34,35,36,37,38,39,40,41,42,

%T 43,44,45,47,48,49,50,51,52,54,55,56,58,59,60,61,62,63,64,65,66,67,68,

%U 69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88

%N Numbers k such that the digits of k (counted with multiplicity) are also digits of binomial(2k,k).

%e Binomial(2*12,12) = 2704156, which contains all digits of 12, so 12 is a term of the sequence.

%K base,less,nonn

%O 1,1

%A _Joseph L. Pe_, Feb 14 2002

%E Revised by _Sean A. Irvine_, Oct 07 2023