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%I #5 Mar 30 2012 17:27:34
%S 1,1,1,3,1,3,1,3,1,3,1,3,1,1,3,1,3,1,1,1,1,3,3,1,3,1,3,1,3,1,1,3,1,3,
%T 1,1,1,1,3,1,3,1,3,1,3,1,3,1,1,3,1,3,1,1,1,1,3,1,3,1,3,1,1,3,1,1,3,0,
%U 3,3,3,3,3,3,1,3,1,3,3,3,3,3,3,1,3,1,3,3,3,3,3,3,1,3,1,3,2,2,2,2,3,2,3,2,1
%N Number of 'Reverse and Add!' operations that have to be applied to the n-th term of A066055 in order to obtain a term in the trajectory of 10583.
%H <a href="/index/Res#RAA">Index entries for sequences related to Reverse and Add!</a>
%e 13597 is the fourth term of A066055. Three 'Reverse and Add!' operations applied to 13597 lead to a term (937838) in the trajectory of 10583, so the corresponding term of the present sequence is 3.
%Y Cf. A023108, A033865, A066054, A066055.
%K base,nonn
%O 0,4
%A _Klaus Brockhaus_, Nov 30 2001