OFFSET
0,2
COMMENTS
a(k) = A064544(k) for k <= 263, a(263) = 1111. But the digits of the next biquam 1113 cannot be arranged to a multiple of 11. So we have a subset of those biquams, whose separating sets differ at most by 1 in size.
MATHEMATICA
Select[Range[0, 300], AnyTrue[FromDigits/@Permutations[ IntegerDigits[ #]], Divisible[ #, 11]&]&] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, Aug 15 2016 *)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Reinhard Zumkeller, Dec 02 2001
STATUS
approved