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%I #8 Sep 04 2021 13:26:10
%S 3,0,14,218,164,7316138,42678240
%N Least m such that the maximal palindrome within the period of the continued fraction for sqrt(m) is the n-th row of Pascal's triangle; or 0 if no such number exists.
%C A056825 is a similar sequence based on the same maximal palindrome.
%e For n=3, continued fraction for sqrt(218) is [[14],[1,3,3,1,28]]. Maximal palindrome in period -> (1,3,3,1) is the 3rd row of Pascal's triangle.
%Y Cf. A003285, A007318.
%K nonn,more
%O 0,1
%A _Naohiro Nomoto_, Nov 13 2001
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