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%I #12 Jul 12 2021 05:37:50
%S 4,64,376,1188,1468,25804,58588,134944,137344,170584,272608,285388,
%T 420208,538732,592408,618448,680704,778804,1163064,1520440,1700944,
%U 2099200,2831008,4020028,4174168,4516108,5059888,5215768,5447272
%N Numbers k such that (k+3)^(k+2) mod (k+1) = k.
%e (4+3)^(4+2) mod (4+1) = 7^6 mod 5 = 117649 mod 5 = 4, so 4 is a term.
%o (PARI) isok(k) = Mod(k+3, k+1)^(k+2) == k; \\ _Michel Marcus_, Jul 12 2021
%Y Equals A055685(n+1) - 2.
%K nonn
%O 1,1
%A Jonathan Ayres (jonathan.ayres(AT)btinternet.com), Oct 26 2001
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