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A064219 a(1) = 1; a(n) > 0; for each k from 1 to n, k divides a(n) or a(n)+1 and a(n) is the least such integer. 2

%I #21 Jun 21 2023 08:03:06

%S 1,1,2,3,15,24,35,119,504,720,2519,2519,41040,83160,83160,196559,

%T 524160,524160,3160079,3160079,3160079,3160079,68468400,68468400,

%U 68468400,68468400,4724319600,4724319600,26702675999,26702675999

%N a(1) = 1; a(n) > 0; for each k from 1 to n, k divides a(n) or a(n)+1 and a(n) is the least such integer.

%H Chai Wah Wu, <a href="/A064219/b064219.txt">Table of n, a(n) for n = 1..112</a>

%H Sean A. Irvine, <a href="https://github.com/archmageirvine/joeis/blob/master/src/irvine/oeis/a064/A064219.java">Java program</a> (github)

%e a(5)=15 because (2 divides a(5)+1) and (3 divides a(5)) and (4 divides a(5)+1) and (5 divides a(5)).

%o (PARI) { a=1; for (n=1, 100, if (a%n && (a+1)%n, until (b, b=1; a++; for (k=1, n, if (a%k && (a+1)%k, b=0; break)))); write("b064219.txt", n, " ", a) ) } \\ _Harry J. Smith_, Sep 10 2009

%o (Python)

%o from math import lcm

%o from itertools import product

%o from sympy.ntheory.modular import solve_congruence

%o def A064219(n):

%o if n == 1: return 1

%o alist, blist, c, klist = [], [], 1, list(range(n,1,-1))

%o while klist:

%o k = klist.pop(0)

%o if not c%k:

%o blist.append(k)

%o else:

%o c = lcm(c,k)

%o alist.append(k)

%o for m in klist.copy():

%o if not k%m:

%o klist.remove(m)

%o for d in product([0,1],repeat=len(alist)):

%o x = solve_congruence(*list(zip(d,alist)))

%o if x is not None:

%o y = x[0]

%o if y > 1:

%o for b in blist:

%o if y%b > 1:

%o break

%o else:

%o if y < c:

%o c = y

%o return int(c-1) # _Chai Wah Wu_, Jun 19 2023

%K easy,nonn

%O 1,3

%A _Don Reble_, Sep 21 2001

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Last modified September 1 18:57 EDT 2024. Contains 375594 sequences. (Running on oeis4.)