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a(n) = Sum_{i=1..n} i^(i+1).
4

%I #18 Mar 26 2019 11:50:58

%S 1,9,90,1114,16739,296675,6061476,140279204,3627063605,103627063605,

%T 3242055440326,110235260819398,4047611646518687,159615707204330911,

%U 6728024062917221536,301875929242270047392,14364960381309995038401

%N a(n) = Sum_{i=1..n} i^(i+1).

%H Seiichi Manyama, <a href="/A062815/b062815.txt">Table of n, a(n) for n = 1..385</a>

%t Accumulate[#^(#+1)&/@Range[17]] (* _Harvey P. Dale_, Mar 18 2011 *)

%o (PARI) a(n) = sum(i=1, n, i^(i+1)); \\ _Michel Marcus_, Mar 26 2019

%Y Cf. A226065, A226140.

%Y Partial sums of A007778. - _Michel Marcus_, Mar 26 2019

%K nonn,easy

%O 1,2

%A _Olivier GĂ©rard_, Jun 23 2001

%E Definition simplified by _Jon E. Schoenfield_, Nov 29 2008