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a(n) = Sum_{i=1..n} i*n^i.
11

%I #16 Feb 13 2024 08:34:26

%S 1,10,102,1252,18555,324726,6565468,150652552,3868151445,109876543210,

%T 3420886930626,115835619046764,4238148192940207,166614350863692382,

%U 7004068093591806840,313512663723845890576,14887093306681068252201,747445606689889243214802

%N a(n) = Sum_{i=1..n} i*n^i.

%H Reinhard Zumkeller, <a href="/A062806/b062806.txt">Table of n, a(n) for n = 1..250</a>

%F a(n) = (n^(n+1)*(n^2-n-1) + n)/(n-1)^2 for n>1. - _Dean Hickerson_, Jun 26, 2001

%F a(n) = n * A068475(n). - _Reinhard Zumkeller_, Nov 22 2014

%t Sum[i*n^i, {i, 1, n}]

%o (Haskell)

%o a062806 n = sum $ zipWith (*) [1..n] $ iterate (* n) n

%o -- _Reinhard Zumkeller_, Nov 22 2014

%Y Cf. A068475.

%K nonn,easy

%O 1,2

%A _Olivier GĂ©rard_, Jun 23 2001