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Integer part of log(n!)^log(log(1 + n)).
2

%I #8 Jun 24 2015 06:43:39

%S 0,1,1,2,3,4,6,8,10,13,16,20,24,29,35,41,48,56,64,74,84,95,107,121,

%T 135,150,167,185,204,225,247,270,295,321,349,379,410,443,478,515,554,

%U 594,637,682,729,778,830,883,940,998,1060,1123,1190,1259,1331,1406

%N Integer part of log(n!)^log(log(1 + n)).

%t Floor[Log[n! ]^Log[Log[1 + n]]]

%o (PARI) a(n) = floor(log(n!)^log(log(1 + n))); \\ _Michel Marcus_, Jun 24 2015

%Y Cf. A062436, close to A055104.

%K nonn,easy

%O 2,4

%A _Olivier GĂ©rard_, Jun 23 2001