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%I #22 Oct 31 2019 01:24:12
%S 3,357,537,1677,3057,51663,66447
%N Numbers k such that the smoothly undulating palindromic number (79*10^k - 97)/99 is a prime.
%C Prime versus probable prime status and proofs are given in the author's table.
%C No further terms < 100000. - _Ray Chandler_, Aug 17 2011
%H Patrick De Geest, <a href="http://www.worldofnumbers.com/undulat.htm#supp797">SUPP Reference Table - 797</a>
%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>
%e k=357 -> (79*10^357 - 97)/99 = 7979797...7979797.
%Y Cf. A062209-A062232, A059758, A032758.
%K nonn,base,more
%O 1,1
%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001
%E a(6)=51663 from _Ray Chandler_, Nov 11 2010
%E a(7)=66447 from _Ray Chandler_, Jan 30 2011
%E Edited by _Ray Chandler_, Aug 17 2011