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a(n) = mu(n)*prime(n).
1

%I #18 May 24 2022 02:26:44

%S 2,-3,-5,0,-11,13,-17,0,0,29,-31,0,-41,43,47,0,-59,0,-67,0,73,79,-83,

%T 0,0,101,0,0,-109,-113,-127,0,137,139,149,0,-157,163,167,0,-179,-181,

%U -191,0,0,199,-211,0,0,0,233,0,-241,0,257,0,269,271,-277,0,-283,293,0,0,313,-317,-331,0,347,-349,-353,0,-367,373,0

%N a(n) = mu(n)*prime(n).

%H Harry J. Smith, <a href="/A062007/b062007.txt">Table of n, a(n) for n=1..1000</a>

%t Table[MoebiusMu[n]*Prime[n], {n, 100}] (* _G. C. Greubel_, May 03 2022 *)

%o (PARI) q=[]; for(n=1,200,q=concat(q,moebius(n)*prime(n))); q

%o (SageMath) [moebius(n)*nth_prime(n) for n in (1..100)] # _G. C. Greubel_, May 03 2022

%Y Cf. A000040, A008683.

%K easy,sign

%O 1,1

%A _Jason Earls_, Jul 04 2001