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a(n) = floor(2^n/(n^2)).
6

%I #13 Jul 03 2018 02:27:57

%S 2,1,0,1,1,1,2,4,6,10,16,28,48,83,145,256,453,809,1452,2621,4755,8665,

%T 15857,29127,53687,99273,184112,342392,638372,1193046,2234634,4194304,

%U 7887910,14861478,28048766,53024287,100393684,190358661,361443664

%N a(n) = floor(2^n/(n^2)).

%H Harry J. Smith, <a href="/A060505/b060505.txt">Table of n, a(n) for n = 1..200</a>

%F a(n) = floor(A000079(n)/A000290(n+1)).

%t Table[Floor[2^w/(w^2)], {w, 1, 40}];

%o (PARI) a(n)={floor(2^n/(n^2))} \\ _Harry J. Smith_, Jul 06 2009

%K easy,nonn

%O 1,1

%A _Labos Elemer_, Apr 11 2001