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a(1) = a(2) = 1; a(n+2) = a(n+1) + a(n+1)^a(n).
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%I #11 Apr 09 2014 10:16:57

%S 1,1,2,4,20,160020

%N a(1) = a(2) = 1; a(n+2) = a(n+1) + a(n+1)^a(n).

%C The next term is 105 digits long.

%t Join[{a=1,b=1},Table[c=b+b^a;a=b;b=c,{n,5}]] (* _Vladimir Joseph Stephan Orlovsky_, Apr 13 2011 *)

%Y Cf. A058523.

%K easy,nonn

%O 1,3

%A _Leroy Quet_, Dec 21 2000