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%I #8 Nov 11 2020 10:31:11
%S 1,1,2,12,16,160,192,2688,3072,18432,122880,1622016,1769472,46006272,
%T 49545216,495452160,594542592,20214448128,21403533312,813334265856,
%U 856141332480,1712282664960,37670218629120,945180031057920
%N a(0) = 1; a(n) = LCM(n, sum{k=0 to n-1}[a(k)]).
%e a(4) = LCM(4, a(0)+a(1)+a(2)+a(3)) = LCM(4, 1+1+2+12) = LCM(4, 16) = 16.
%K nonn
%O 0,3
%A _Leroy Quet_, Nov 08 2000
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