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Prime recurrence: a(n+1) = a(n)-th prime, with a(1) = 6.
8

%I #25 Jul 18 2021 16:33:33

%S 6,13,41,179,1063,8527,87803,1128889,17624813,326851121,7069067389,

%T 175650481151,4952019383323,156740126985437,5519908106212193,

%U 214616508361122337,9150317141480822981

%N Prime recurrence: a(n+1) = a(n)-th prime, with a(1) = 6.

%C _Lubomir Alexandrov_ informs me that he studied this sequence in his 1965 notebook. - _N. J. A. Sloane_, May 23 2008

%H Lubomir Alexandrov, <a href="https://arxiv.org/abs/math/9811096">On the nonasymptotic prime number distribution</a>, 1998 preprint, arXiv:math/9811096 [math.NT] (See Appendix.)

%H Lubomir Alexandrov, <a href="http://www1.jinr.ru/Preprints/2002/055(E5-2002-55).pdf">Prime Number Sequences And Matrices Generated By Counting Arithmetic Functions</a>, Communications of the Joint Institute of Nuclear Research, E5-2002-55, Dubna, 2002.

%t NestList[ Prime, 6, 13 ]

%Y Cf. A007097, A057450, A057452, A057453.

%K nonn,hard,more

%O 1,1

%A _Robert G. Wilson v_, Sep 26 2000

%E a(14) from _Ray Chandler_, Nov 04 2004

%E a(15)-a(17) from _Robert G. Wilson v_, Mar 07 2017 using Kim Walisch's primecount