%I #16 Nov 15 2014 08:41:52
%S 1,2,11,1,2,2,1,1,11,2,7,1,2,3,2,1,1,7,1,2,2,7,4,1,2,1,1,2,23,2,2,1,
%T 15,1,1,4,3,4,1,2,4,2,2,1,28,7,3,2,10,2,6,1,1,2,1,6,1,1,3,3,9,26,3,1,
%U 2,16,2,2,1,8,1,2,1,1,69,1,1,2,2,1,5,3,1,2,2,1,1,1,1,1,68,1,1,1,1,1,2
%N Second term of continued fraction for exp(n).
%H Eric M. Schmidt, <a href="/A057213/b057213.txt">Table of n, a(n) for n = 1..10000</a>
%F floor(1/(exp(n)-floor(exp(n))))
%t Table[ContinuedFraction[Exp[n],3][[2]],{n,100}] (* _Harvey P. Dale_, Nov 15 2014 *)
%o (PARI) default(realprecision, 10000);
%o for(n=1, 10000, print(n, " ", contfrac(exp(n))[2]))
%o \\ _Eric M. Schmidt_, Mar 05 2014
%Y Cf. A138324.
%K easy,nonn
%O 1,2
%A _Leroy Quet_, Sep 29 2000