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a(n) = floor(11^11/n).
1

%I #12 Aug 12 2023 11:05:27

%S 285311670611,142655835305,95103890203,71327917652,57062334122,

%T 47551945101,40758810087,35663958826,31701296734,28531167061,

%U 25937424601,23775972550,21947051585,20379405043,19020778040

%N a(n) = floor(11^11/n).

%H Seiichi Manyama, <a href="/A057073/b057073.txt">Table of n, a(n) for n = 1..10000</a>

%t With[{c=11^11},Table[Floor[c/n],{n,20}]] (* _Harvey P. Dale_, Jun 10 2022 *)

%o (PARI) a(n) = 11^11\n; \\ _Seiichi Manyama_, Aug 12 2023

%Y Cf. A000007, A033324, A033347, A057066-A057075.

%K nonn,easy

%O 1,1

%A _Henry Bottomley_, Jul 31 2000