A055191 Cumulative counting sequence: method A (adjective-before-noun) pairs, starting with 5.

5, 1, 5, 2, 5, 1, 1, 3, 5, 3, 1, 1, 2, 4, 5, 5, 1, 2, 2, 2, 3, 6, 5, 6, 1, 5, 2, 3, 3, 1, 4, 8, 5, 8, 1, 6, 2, 5, 3, 2, 4, 2, 6, 10, 5, 9, 1, 9, 2, 6, 3, 3, 4, 4, 6, 2, 8, 11, 5, 10, 1, 11, 2, 8, 3, 5, 4, 6, 6, 3, 8, 1, 10, 2, 9, 13, 5, 12, 1, 13, 2, 10, 3, 6, 4, 8

Offset

1,1

Comments

Segments (generated as at A217760): 5; 1,5; 2,5,1,1; 3,5,3,1,1,2; ... The 4th segment is read "3 5's and 3 1's and 1 2" as a record of what was previously written; 3,3,1 are adjectives and 5 1 2 are nouns. Conjecture: every nonnegative integer occurs. - Clark Kimberling, Mar 25 2013

Links

Seiichi Manyama, Table of n, a(n) for n = 1..10000

Example

Write 5, thus having 1 5, thus having 2 5's and 1 1, thus having 3 5's and 3 1's and 1 2, etc.

Mathematica

s = {5}; Do[s = Flatten[{s, {Count[s, #], #} & /@ DeleteDuplicates[s]}], {14}]; s (* Peter J. C. Moses, Mar 21 2013 *)

Crossrefs

Cf. A217760, A217780.

Sequence in context: A264483 A050340 A021955 * A299628 A217774 A060186

Adjacent sequences: A055188 A055189 A055190 * A055192 A055193 A055194

Keyword

nonn

Author

Clark Kimberling, Apr 27 2000

Status

approved