

A055191


Cumulative counting sequence: method A (adjectivebeforenoun) pairs, starting with 5.


3



5, 1, 5, 2, 5, 1, 1, 3, 5, 3, 1, 1, 2, 4, 5, 5, 1, 2, 2, 2, 3, 6, 5, 6, 1, 5, 2, 3, 3, 1, 4, 8, 5, 8, 1, 6, 2, 5, 3, 2, 4, 2, 6, 10, 5, 9, 1, 9, 2, 6, 3, 3, 4, 4, 6, 2, 8, 11, 5, 10, 1, 11, 2, 8, 3, 5, 4, 6, 6, 3, 8, 1, 10, 2, 9, 13, 5, 12, 1, 13, 2, 10, 3, 6, 4, 8
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OFFSET

1,1


COMMENTS

Segments (generated as at A217760): 5; 1,5; 2,5,1,1; 3,5,3,1,1,2; ... The 4th segment is read "3 5's and 3 1's and 1 2" as a record of what was previously written; 3,3,1 are adjectives and 5 1 2 are nouns. Conjecture: every nonnegative integer occurs.  Clark Kimberling Mar 25 2013


LINKS

Table of n, a(n) for n=1..86.


EXAMPLE

Write 5, thus having 1 5, thus having 2 5's and 1 1, thus having 3 5's and 3 1's and 1 2, etc.


MATHEMATICA

s = {5}; Do[s = Flatten[{s, {Count[s, #], #} & /@ DeleteDuplicates[s]}], {14}]; s (* Peter J. C. Moses, Mar 21 2013 *)


CROSSREFS

Cf. A217760, A217780.
Sequence in context: A264483 A050340 A021955 * A217774 A060186 A240995
Adjacent sequences: A055188 A055189 A055190 * A055192 A055193 A055194


KEYWORD

nonn


AUTHOR

Clark Kimberling, Apr 27 2000


STATUS

approved



