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A054030 Sigma(n)/n for n such that sigma(n) is divisible by n. 15

%I #28 Oct 27 2023 22:00:46

%S 1,2,2,3,2,3,2,4,4,3,4,4,2,4,4,3,4,3,2,5,5,4,3,4,2,4,4,5,4,5,5,4,5,5,

%T 4,4,4,5,4,4,2,5,4,5,6,5,5,5,5,5,5,6,5,5,4,5,6,5,4,4,5,4,5,4,6,6,6,6,

%U 6,6,6,6,5,6,6,5,6,5,6,6,5,4,4,5,4,4,5,6,5,5,4,6,4,4,6,5,6,6,6,6,6,6,6,5,6

%N Sigma(n)/n for n such that sigma(n) is divisible by n.

%C The graph supports the conjecture that all numbers except 2 appear only a finite number of times. Sequences A000396, A005820, A027687, A046060 and A046061 give the n for which the abundancy sigma(n)/n is 2, 3, 4, 5 and 6, respectively. See A134639 for the number of n having abundancy greater than 2. - _T. D. Noe_, Nov 04 2007

%H T. D. Noe, <a href="/A054030/b054030.txt">Table of n, a(n) for n = 1..1600</a> (using Flammenkamp's data)

%H Achim Flammenkamp, <a href="http://wwwhomes.uni-bielefeld.de/achim/mpn.html">The Multiply Perfect Numbers Page</a>

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/Abundancy.html">Abundancy</a>

%F a(n) = sigma(A007691(n))/A007691(n)

%p with(numtheory): for i while i < 33000 do

%p if sigma(i) mod i = 0 then print(sigma(i)/i) fi od;

%o (PARI) for(n=1,1e7,if(denominator(k=sigma(n,-1))==1, print1(k", "))) \\ _Charles R Greathouse IV_, Mar 09 2014

%Y Cf. A000203, A007691, A054024, A065997, A219545.

%K nonn,easy

%O 1,2

%A _Asher Auel_, Jan 19 2000

%E More terms from _Jud McCranie_, Jul 09 2000

%E More terms from _David Wasserman_, Jun 28 2004

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Last modified September 17 11:15 EDT 2024. Contains 375987 sequences. (Running on oeis4.)