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a(n+1) = a(n)^2 + n*(n+3)*a(n).
0

%I #9 Aug 14 2021 12:16:38

%S 1,5,75,6975,48845925,2385926342942625,

%T 5692644513947697441166560792375,

%U 32406201562178816446780055667981084047163520943188247113606875

%N a(n+1) = a(n)^2 + n*(n+3)*a(n).

%C Each term divides the next.

%H S. A. Fulling, <a href="http://arxiv.org/abs/quant-ph/9911051">Large Numbers, the Chinese Remainder Theorem, and the Circle of Fifths</a>, arXiv:quant-ph/9911051

%e 75=5^2+2*5*5=25+50.

%t nxt[{n_,a_}]:={n+1,a^2+a(n+1)(n+4)}; NestList[nxt,{0,1},10][[All,2]] (* _Harvey P. Dale_, Aug 14 2021 *)

%K easy,nonn

%O 0,2

%A Dennis S. Kluk (mathemagician(AT)ameritech.net)

%E Corrected by _Harvey P. Dale_, Aug 14 2021