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A051109 Hyperinflation sequence for banknotes. 3
1, 2, 5, 10, 20, 50, 100, 200, 500, 1000, 2000, 5000, 10000, 20000, 50000, 100000, 200000, 500000, 1000000, 2000000, 5000000, 10000000, 20000000, 50000000, 100000000, 200000000, 500000000, 1000000000, 2000000000, 5000000000 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

Denominations of Polish banknotes circa 1995.

English coins in 2006 have denominations of 1, 2, 5, 10, 20, 50, 100, 200 pence.

LINKS

Table of n, a(n) for n=0..29.

FORMULA

a(3n)=10^n, a(3n+1)=2*10^n, a(3n+2)=5*10^n

a(n) = [(n%3)^2 + 1]*10^floor(n/3). E.g. a(0) = [(0%3)^2 + 1]*10^floor(0/3) = [0^2 + 1]*10^0 = 1, a(4) = [(4%3)^2 + 1]*10^floor(4/3) = [1^2 + 1]*10^1 = 20, a(8) = [(8%3)^2 + 1]*10^floor(8/3) = [2^2 + 1]*10^2 = 500. - Justin L. Brown (jlbrown(AT)neo.tamu.edu), Jun 17 2004

G.f.: (1+2*x+5*x^2)/(1-10*x^3). - Philippe Deléham, Apr 08 2013

a(n) = 10*a(n-3) with n>2, a(0)=1, a(1)=2, a(2)=5. - Philippe Deléham, Apr 08 2013

PROG

(Python) print( [ ((n % 3) ** 2 + 1) * 10**int(n/3) for n in range(100)] )

CROSSREFS

Cf. A117727.

Sequence in context: A330456 A176692 A212951 * A124146 A262408 A344378

Adjacent sequences:  A051106 A051107 A051108 * A051110 A051111 A051112

KEYWORD

easy,nonn

AUTHOR

Robert Lozyniak (11(AT)onna.com)

EXTENSIONS

Second formula corrected by Peter C. Lauterbach, Nov 12 2010

STATUS

approved

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Last modified September 28 19:16 EDT 2021. Contains 347717 sequences. (Running on oeis4.)