%I #16 Dec 17 2020 14:27:12
%S 1,1,1,1,1,2,1,1,1,1,1,2,1,1,1,1,1,2,1,1,1,1,1,2,2,3,1,1,1,2,3,2,2,2,
%T 1,3,2,1,1,1,3,1,2,1,1,3,1,1,2,2,1,3,1,1,1,2,3,1,1,2,2,3,2,2,1,1,3,2,
%U 1,1,1,3,1,2,2,1,1,3,1,1,2,1,3,1,1,1,2,3,1,2
%N Length of longest palindromic subword of (n base 5).
%H Robert Israel, <a href="/A050433/b050433.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) <= min(a(5*n+k): 0 <= k < 5). [_Reinhard Zumkeller_, Jul 31 2011]
%p LPS:= proc(L) local nL,n,i;
%p nL:= nops(L);
%p for n from nL to 1 by -1 do
%p for i from 1 to nL-n+1 do
%p if L[i..i+n-1] = ListTools:-Reverse(L[i..i+n-1]) then return n fi
%p od od:
%p end proc:
%p seq(LPS(convert(n,base,5)),n=1..100); # _Robert Israel_, Dec 17 2020
%Y Cf. A050430, A050431, A050432
%K nonn,base
%O 1,6
%A _Clark Kimberling_