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%I #5 Mar 30 2012 18:35:38
%S 9314,27849,30993,36398,46142,46405,55686,68653,69765,74416,74924,
%T 83718,84934,86662,86696,90177,92915,97533,97629,99895,101823,106538,
%U 111498,116182,116225,119005,119618,119874,122506,124414,124467,129236
%N Becomes prime or 4 after exactly 10 iterations of f(x) = sum of prime factors of x.
%C f(x) = sum of prime factors with multiplicity, so that f(1500) = 2+2+3+5+5+5 = 22.
%K nonn
%O 1,1
%A _David W. Wilson_
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