OFFSET
1,1
COMMENTS
f(x) = sum of prime factors with multiplicity, so that f(1500) = 2+2+3+5+5+5 = 22.
LINKS
Harvey P. Dale, Table of n, a(n) for n = 1..3500
MATHEMATICA
nxt[n_]:=Total[Flatten[Table[#[[1]], {#[[2]]}]&/@FactorInteger[n]]]; sixiQ[ n_]:=Module[{c=NestList[nxt, n, 6]}, PrimeQ[c]=={False, False, False, False, False, False, True} || FirstPosition[ c, 4, 1] == {7}]; Select[ Range[ 1200], sixiQ] (* Harvey P. Dale, Oct 21 2014 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
STATUS
approved