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%I #5 Mar 30 2012 18:35:38
%S 62,69,74,94,106,116,123,133,169,178,188,190,201,206,228,238,244,254,
%T 259,267,286,291,292,305,321,327,340,344,365,366,370,381,387,395,403,
%U 404,408,411,413,438,444,446,453,459,465,471,472,474,482,483,484,496
%N Becomes prime or 4 after exactly 5 iterations of f(x) = sum of prime factors of x.
%C f(x) = sum of prime factors with multiplicity, so that f(1500) = 2+2+3+5+5+5 = 22.
%K nonn
%O 1,1
%A _David W. Wilson_
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