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a(n) = (5^n + 3)/4.
9

%I #30 Dec 11 2023 08:37:54

%S 1,2,7,32,157,782,3907,19532,97657,488282,2441407,12207032,61035157,

%T 305175782,1525878907,7629394532,38146972657,190734863282,

%U 953674316407,4768371582032,23841857910157,119209289550782,596046447753907

%N a(n) = (5^n + 3)/4.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (6,-5).

%F a(n) = A047848(2,n).

%F From _Philippe Deléham_, Oct 06 2009: (Start)

%F a(n) = 6*a(n-1) - 5*a(n-2) for n > 1.

%F G.f.: (1-4*x)/((1-x)*(1-5*x)). (End)

%F a(n) = 5*a(n-1) - 3 (with a(0)=1). - _Vincenzo Librandi_, Aug 06 2010

%F From _Elmo R. Oliveira_, Dec 10 2023: (Start)

%F a(n) = A132079(n)/2.

%F E.g.f.: (1/4)*(exp(5*x) + 3*exp(x)). (End)

%o (PARI) a(n)=(5^n+3)/4 \\ _Charles R Greathouse IV_, Oct 07 2015

%Y Cf. A047848, A132079.

%K nonn,easy

%O 0,2

%A _Clark Kimberling_

%E Better description from _Michael Somos_