%I #22 Dec 27 2023 00:06:18
%S 26,7,2,4,3,1,1,25,1,1,3,4,2,7,52,7,2,4,3,1,1,25,1,1,3,4,2,7,52,7,2,4,
%T 3,1,1,25,1,1,3,4,2,7,52,7,2,4,3,1,1,25,1,1,3,4,2,7,52,7,2,4,3,1,1,25,
%U 1,1,3,4,2,7,52,7,2,4,3,1,1,25,1,1,3,4,2,7,52,7,2
%N Continued fraction for sqrt(683).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_14">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(683)),confrac);
%t ContinuedFraction[Sqrt[683],120] (* _Harvey P. Dale_, Jun 13 2011 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_