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Continued fraction for sqrt(621).
2

%I #22 Jun 28 2026 21:36:57

%S 24,1,11,2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,48,1,11,

%T 2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,

%U 48,1,11,2,11,1,48,1,11,2,11,1,48,1,11,2,11,1,48,1,11

%N Continued fraction for sqrt(621).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(621)),confrac);

%t ContinuedFraction[Sqrt[621],100] (* _Harvey P. Dale_, Jun 07 2025 *)

%t (* Alternative: *)

%t PadRight[{24},100,{48,1,11,2,11,1}] (* _Harvey P. Dale_, Jun 07 2025 *)

%K nonn,cofr,easy,less,changed

%O 0,1

%A _N. J. A. Sloane_