%I #15 Jul 08 2025 23:29:48
%S 24,2,2,2,1,1,1,6,2,1,9,12,9,1,2,6,1,1,1,2,2,2,48,2,2,2,1,1,1,6,2,1,9,
%T 12,9,1,2,6,1,1,1,2,2,2,48,2,2,2,1,1,1,6,2,1,9,12,9,1,2,6,1,1,1,2,2,2,
%U 48,2,2,2,1,1,1,6,2,1,9,12,9,1,2,6,1,1,1,2,2,2,48,2
%N Continued fraction for sqrt(596).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_22">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(596)),confrac);
%t ContinuedFraction[Sqrt[596],120] (* _Harvey P. Dale_, May 11 2011 *)
%K nonn,cofr,easy,less
%O 0,1
%A _N. J. A. Sloane_