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A040539 Continued fraction for sqrt(563). 1

%I #16 Dec 27 2023 00:47:08

%S 23,1,2,1,2,23,2,1,2,1,46,1,2,1,2,23,2,1,2,1,46,1,2,1,2,23,2,1,2,1,46,

%T 1,2,1,2,23,2,1,2,1,46,1,2,1,2,23,2,1,2,1,46,1,2,1,2,23,2,1,2,1,46,1,

%U 2,1,2,23,2,1,2,1,46,1,2,1,2,23,2,1,2,1,46,1,2,1,2

%N Continued fraction for sqrt(563).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,1).

%F From _Amiram Eldar_, Dec 27 2023: (Start)

%F Multiplicative with a(2^e) = 2, a(5^e) = 23, and a(p^e) = 1 for an odd p != 5.

%F Dirichlet g.f.: zeta(s) * (1 + 1/2^s) * (1 + 22/5^s). (End)

%p with(numtheory): Digits := 300: convert(evalf(sqrt(563)),confrac);

%t ContinuedFraction[Sqrt[563], 100] (* _Amiram Eldar_, Dec 27 2023 *)

%K nonn,cofr,easy,less,mult

%O 0,1

%A _N. J. A. Sloane_

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