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Continued fraction for sqrt(423).
3

%I #16 Dec 27 2023 00:51:37

%S 20,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,

%T 40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,

%U 40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1,40,1,1,3,4,3,1,1

%N Continued fraction for sqrt(423).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(423)),confrac);

%t ContinuedFraction[Sqrt[423],100] (* or *) PadRight[{20},100,{40,1,1,3,4,3,1,1}] (* _Harvey P. Dale_, Jan 03 2023 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.