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Continued fraction for sqrt(309).
0

%I #14 Jul 22 2022 17:46:40

%S 17,1,1,2,1,2,4,1,1,1,8,6,1,10,1,6,8,1,1,1,4,2,1,2,1,1,34,1,1,2,1,2,4,

%T 1,1,1,8,6,1,10,1,6,8,1,1,1,4,2,1,2,1,1,34,1,1,2,1,2,4,1,1,1,8,6,1,10,

%U 1,6,8,1,1,1,4,2,1,2,1,1,34,1,1,2,1,2,4,1,1,1,8,6

%N Continued fraction for sqrt(309).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_26">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(309)),confrac);

%t ContinuedFraction[Sqrt[309],100] (* _Harvey P. Dale_, May 16 2012 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.