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Continued fraction for sqrt(267).
1

%I #14 Dec 27 2023 01:16:04

%S 16,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,

%T 2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,

%U 1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1,15,1,2,32,2,1

%N Continued fraction for sqrt(267).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(267)),confrac);

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.