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%I #16 Dec 27 2023 00:01:11
%S 16,5,2,1,2,1,10,16,10,1,2,1,2,5,32,5,2,1,2,1,10,16,10,1,2,1,2,5,32,5,
%T 2,1,2,1,10,16,10,1,2,1,2,5,32,5,2,1,2,1,10,16,10,1,2,1,2,5,32,5,2,1,
%U 2,1,10,16,10,1,2,1,2,5,32,5,2,1,2,1,10,16,10,1,2
%N Continued fraction for sqrt(262).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_14">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(262)),confrac);
%t ContinuedFraction[Sqrt[262],120] (* _Harvey P. Dale_, Mar 13 2014 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.