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Continued fraction for sqrt(248).
1

%I #17 Nov 29 2023 05:20:11

%S 15,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,

%T 2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,

%U 30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1,30,1,2,1

%N Continued fraction for sqrt(248).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,1).

%F From _Amiram Eldar_, Nov 29 2023: (Start)

%F Multiplicative with a(2) = 2, a(2^e) = 30 for e >= 2, and a(p^e) = 1 for an odd prime p.

%F Dirichlet g.f.: zeta(s) * (1 + 1/2^s + 7/4^(s-1)). (End)

%p with(numtheory): Digits := 300: convert(evalf(sqrt(248)),confrac);

%t ContinuedFraction[Sqrt[248], 100] (* _Amiram Eldar_, Nov 29 2023 *)

%K nonn,cofr,easy,mult

%O 0,1

%A _N. J. A. Sloane_