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Continued fraction for sqrt(245).
2

%I #16 Dec 27 2023 00:30:18

%S 15,1,1,1,7,6,7,1,1,1,30,1,1,1,7,6,7,1,1,1,30,1,1,1,7,6,7,1,1,1,30,1,

%T 1,1,7,6,7,1,1,1,30,1,1,1,7,6,7,1,1,1,30,1,1,1,7,6,7,1,1,1,30,1,1,1,7,

%U 6,7,1,1,1,30,1,1,1,7,6,7,1,1,1,30,1,1,1,7,6,7,1,1,1

%N Continued fraction for sqrt(245).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(245)),confrac);

%t ContinuedFraction[Sqrt[245],100] (* or *) PadRight[{15},100,{30,1,1,1,7,6,7,1,1,1}] (* _Harvey P. Dale_, Sep 26 2016 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.