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Continued fraction for sqrt(233).
2

%I #16 Dec 27 2023 00:53:19

%S 15,3,1,3,1,1,1,1,3,1,3,30,3,1,3,1,1,1,1,3,1,3,30,3,1,3,1,1,1,1,3,1,3,

%T 30,3,1,3,1,1,1,1,3,1,3,30,3,1,3,1,1,1,1,3,1,3,30,3,1,3,1,1,1,1,3,1,3,

%U 30,3,1,3,1,1,1,1,3,1,3,30,3,1,3,1,1,1,1,3,1,3,30,3

%N Continued fraction for sqrt(233).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(233)),confrac);

%t ContinuedFraction[Sqrt[233],120] (* or *) PadRight[{15},120,{30,3,1,3,1,1,1,1,3,1,3}] (* _Harvey P. Dale_, May 19 2023 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.