A036909 a(n) = (2/3) * 4^n * binomial(3*n, n).

8, 160, 3584, 84480, 2050048, 50692096, 1270087680, 32133218304, 819082035200, 21002987765760, 541167892561920, 13999778090188800, 363391162981023744, 9459706464902840320, 246865719056498950144, 6456334894356662059008

Offset

1,1

References

Identity (3.116) in H. W. Gould, Combinatorial Identities, Morgantown, 1972, page 35.

Links

G. C. Greubel, Table of n, a(n) for n = 1..695

Formula

Sum_{k=0..n} binomial(4*n, 2*(n-k))*binomial(k+n, n) = (2/3)*4^n*binomial(3*n, n) = (2/3)*4^n*A005809(n) = 2*4^n*A025174(n).

G.f.: (2/3) * 2F1([1/3, 2/3], [1/2], 27*x) = 2*(cos((1/6)*arccos(1-54*x))/sqrt(1-27*x) - 1) /(3*x). - Harvey P. Dale, Mar 26 2012

D-finite with recurrence n*(2*n-1)*a(n) = 6*(3*n-1)*(3*n-2)*a(n-1). - R. J. Mathar, Feb 08 2021

G.f.: (2/3)*( cos((1/3)*Arcsin(3*sqrt(3*x)))/sqrt(1-27*x) - 1). - G. C. Greubel, Jun 22 2022

Mathematica

Table[2/3 4^n Binomial[3n, n], {n, 20}](* Harvey P. Dale, Mar 26 2012 *)

Prog

(Magma) [(2/3)*4^n*Binomial(3*n, n): n in [1..30]]; // G. C. Greubel, Jun 22 2022
(SageMath) [(2/3)*4^n*binomial(3*n, n) for n in (0..30)] # G. C. Greubel, Jun 22 2022

Crossrefs

Cf. A005809, A025174.

Sequence in context: A127369 A364741 A228700 * A369539 A221077 A052140

Adjacent sequences: A036906 A036907 A036908 * A036910 A036911 A036912

Keyword

nonn

Author

N. J. A. Sloane

Status

approved