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a(0)=2; a(n) is the smallest k > a(n-1) such that the fractional part of k^(1/10) starts with n.
2

%I #15 Nov 27 2017 02:49:04

%S 2,3,7,14,29,58,110,202,358,614,1668,1750,1834,1923,2015,2111,2211,

%T 2316,2425,2538,2656,2780,2908,3042,3181,3326,3477,3633,3797,3967,

%U 4143,4327,4518,4716,4923,5137,5360,5591,5832,6082,6341,6610,6889,7179,7480

%N a(0)=2; a(n) is the smallest k > a(n-1) such that the fractional part of k^(1/10) starts with n.

%F For n > 0, a(n) = ceiling((d + n/10^d)^10) where d = 1 + floor(log_10(n)). - _Jon E. Schoenfield_, Nov 26 2017

%e a(7)=202 -> 202^(1/10) = 1.{7}0033751...;

%e a(8)=358 -> 358^(1/10) = 1.{8}0048000... and a(7)=202 < a(8)=358.

%e From _Jon E. Schoenfield_, Nov 26 2017: (Start)

%e n a(n) a(n)^(1/10)

%e -- ----- ---------------

%e 0 2 1.{0}7177346...

%e 1 3 1.{1}1612317...

%e 2 7 1.{2}1481404...

%e 3 14 1.{3}0200545...

%e 4 29 1.{4}0036033...

%e 5 58 1.{5}0086904...

%e 6 110 1.{6}0007105...

%e 7 202 1.{7}0033751...

%e 8 358 1.{8}0048000...

%e 9 614 1.{9}0027667...

%e 10 1668 2.{10}000149...

%e 11 1750 2.{11}010372...

%e 12 1834 2.{12}001987...

%e ...

%e 99 57110 2.{99}000019...

%e 100 81963 3.{100}00064...

%e 101 82228 3.{101}00147... (End)

%Y Cf. A034065, A034085.

%K nonn,base

%O 0,1

%A _Patrick De Geest_, Sep 15 1998

%E Name edited by _Jon E. Schoenfield_, Nov 26 2017