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Product t2(q^d); d | 15, where t2 = theta2(q)/(2*q^(1/4)).
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%I #14 May 29 2017 09:46:02

%S 1,1,0,2,1,1,3,0,2,3,2,2,1,1,2,6,2,1,7,4,3,7,0,4,10,4,4,2,4,5,10,4,1,

%T 13,6,4,12,1,4,14,5,4,3,6,5,15,8,0,16,6,8,20,2,8,18,8,8,3,8,8,25,9,2,

%U 20,7,10,21,2,10,25,8,12,1,12,12,24,10,1,30,8,9,28

%N Product t2(q^d); d | 15, where t2 = theta2(q)/(2*q^(1/4)).

%C Also the number of positive odd solutions to equation a^2 + 3*b^2 + 5*c^2 + 15*d^2 = 8*n + 24. - _Seiichi Manyama_, May 29 2017

%H Seiichi Manyama, <a href="/A033774/b033774.txt">Table of n, a(n) for n = 0..10000</a>

%K nonn

%O 0,4

%A _N. J. A. Sloane_

%E More terms from _Seiichi Manyama_, May 23 2017