%I #9 Aug 06 2016 09:55:17
%S 0,180,1152,4320,29700,63360,123552,224640,386100,633600,1527552,
%T 2267460,3283200,4651200,6462720,8825652,15732000,20592000,26640900,
%U 34100352,43221600,54288000,83566080,102529152,124945920,151301700
%N Integer quotients n(n+1)(n+2)...(n+6) / (n+(n+1)+(n+2)+...+(n+6)).
%C S(A016873) = (5n+2) gives values n so that above divisions end with digit '2'.
%t f[n_]:=Module[{r=Range[0,6]+n},Times@@r/Total[r]]; Select[f/@Range[0,50], IntegerQ] (* _Harvey P. Dale_, Mar 20 2011 *)
%Y Cf. A032774, A032775.
%K nonn
%O 0,2
%A _Patrick De Geest_, May 15 1998