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Integer quotients n(n+1)(n+2)...(n+6) / (n+(n+1)+(n+2)+...+(n+6)).
2

%I #9 Aug 06 2016 09:55:17

%S 0,180,1152,4320,29700,63360,123552,224640,386100,633600,1527552,

%T 2267460,3283200,4651200,6462720,8825652,15732000,20592000,26640900,

%U 34100352,43221600,54288000,83566080,102529152,124945920,151301700

%N Integer quotients n(n+1)(n+2)...(n+6) / (n+(n+1)+(n+2)+...+(n+6)).

%C S(A016873) = (5n+2) gives values n so that above divisions end with digit '2'.

%t f[n_]:=Module[{r=Range[0,6]+n},Times@@r/Total[r]]; Select[f/@Range[0,50], IntegerQ] (* _Harvey P. Dale_, Mar 20 2011 *)

%Y Cf. A032774, A032775.

%K nonn

%O 0,2

%A _Patrick De Geest_, May 15 1998