|
%I #7 Feb 12 2016 13:12:04
%S 2038,2149,2179,2389,2791,2974,3193,3921,3943,4027,4101,4126,4237,
%T 4417,4601,4691,4701,4801,4969,5023,5209,5279,5737,5836,5926,5961,
%U 6029,6046,6346,6393,6429,6449,6491,6521,6526,6547,6718,6733,6799,6811,6826,6847
%N Period of continued fraction for sqrt(n) contains exactly 38 ones.
%t cf38Q[n_]:=Module[{s=Sqrt[n]},If[IntegerQ[s],1,Count[ ContinuedFraction[ s][[2]],1]]==38]; Select[Range[7000],cf38Q] (* _Harvey P. Dale_, Feb 12 2016 *)
%K nonn
%O 1,1
%A _David W. Wilson_
|
