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a(n)=(# 2's)-(# 3's) in first n terms of A031235.
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%I #4 Mar 30 2012 18:56:21

%S 0,1,0,0,0,0,0,0,1,1,0,0,0,0,0,1,1,2,3,4,3,4,4,5,5,4,4,3,4,3,2,1,1,0,

%T 0,0,0,0,1,1,0,0,0,0,0,0,0,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,

%U 0,0,0,0,0,0,0,1,1,1,2,2,3,4,4,3,4,4,4,5,5,5

%N a(n)=(# 2's)-(# 3's) in first n terms of A031235.

%K nonn

%O 1,18

%A _Clark Kimberling_